I need help with this one question; can someone please help?
Give any three ordered pairs that are solutions of the equation:
2x - 3y= 12
I already have one (9,2)
Thanks!
-MC
pick any even number for y,
say y = 4
then 2x-12 = 12
2x = 24
x = 12 -----> (12,4)
try another one.
You can check if your point is correct by subbing it back in
You posted this same type question earlier and were given a response by Rick P that said your two answers were correct and explained what you needed to do to make as many ordered pairs as needed. Just use that same procedure for this one. If you post your solutions someone will be glad to check them.
OK, Thanks to both of you.
I will be sure to post when I get the solution
-MC
Sure, I'd be happy to help! To find three ordered pairs that are solutions to the equation 2x - 3y = 12, we can choose any values for x and solve for y. Let's go step by step.
Let's start with the given solution (9, 2). We can confirm if it is indeed a solution of the equation by substituting these values into the equation:
2(9) - 3(2) = 18 - 6 = 12
Since the equation holds true with these values, (9, 2) is indeed a solution.
Now, let's find two more solutions:
1. Choose a value for x. Let's say x = 0.
Substitute x = 0 into the equation: 2(0) - 3y = 12.
Simplify the equation: -3y = 12.
Solve for y: y = 12 / -3 = -4.
So, the first additional solution is (0, -4).
2. Choose another value for x. Let's say x = 6.
Substitute x = 6 into the equation: 2(6) - 3y = 12.
Simplify the equation: 12 - 3y = 12.
Solve for y: -3y = 0.
So, y can be any value. Let's say y = 0.
The second additional solution is (6, 0).
Therefore, in addition to (9, 2), two additional solutions to the equation 2x - 3y = 12 are (0, -4) and (6, 0).
I hope this helps! Let me know if you have any further questions.