The horizontal motion of a horizontally launched projectile affects its vertical motion. (FALSE)
A missile launches at a velocity of 30.0 m/s at an angle of 30.0* to the normal. What is the maximum height the missile attains? (11.5 m, I'm not very sure)
In calculating the force of gravity between two objects, if the distance between the objects is increased 4 times, the force of gravity will (DECREASE BY 1/16)
In calculating the force of gravity between two objects, if the distance between the objects is increased 4 times, the force of gravity will (DECREASE BY 1/16)
Actually, it will be decreased TO 1/16 of the original force. The way you stated it, the force would be decreased BY 1/16, making it 15/16 of the original force.
To determine the maximum height attained by the missile, we need to analyze the vertical motion of the projectile.
The horizontal motion of a horizontally launched projectile does not affect its vertical motion. This is because the horizontal and vertical motions are independent of each other. The only factor that affects the vertical motion of a projectile is the force of gravity acting in the downward direction.
Now, let's calculate the maximum height using the given information. We can use the equations of motion to determine the height reached by the missile.
Given:
Initial velocity (u) = 30.0 m/s
Launch angle (θ) = 30.0 degrees
To find the maximum height, we need to determine the time it takes for the missile to reach its maximum height. We can calculate this using the vertical component of the initial velocity.
Vertical component of velocity (v_y) = u * sin(θ)
v_y = 30.0 m/s * sin(30.0 degrees)
v_y = 15.0 m/s
Using the equation of motion:
v_y = u_y + gt
where:
v_y is the final vertical velocity,
u_y is the initial vertical velocity,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
t is the time.
We can solve this equation for time:
15.0 m/s = 0 + (9.8 m/s^2) * t
t = 15.0 m/s / 9.8 m/s^2
t ≈ 1.53 s
Next, we can determine the maximum height (h) attained by the missile using the equation of motion:
h = u_y * t - 0.5 * g * t^2
h = 15.0 m/s * 1.53 s - 0.5 * 9.8 m/s^2 * (1.53 s)^2
h ≈ 11.57 m
Therefore, the maximum height the missile attains is approximately 11.57 meters.