Posted by deranged on Tuesday, May 5, 2009 at 5:14pm.
I need a jump start in setting up the equations etc when solving for vertex, line of symmetry and deciding maximum/minimum This is the problem I am starting with
f(x)= 2x^2+2x+8 We are looking for the vertex, line of symmetry and the max/minimum I cannot seem to get this started. Thank you

Algebra  drwls, Tuesday, May 5, 2009 at 6:05pm
Rewrite f(x) by completing the square:
f(x) = 2(x^2  x + 1/4) + 8.5
= 2 (x  1/2)^2 + 8.5
The vertex is where f(x) has its maximum value. This is where x = 1/2. At that x value, f(x) = 8.5
There is no minimum value.
The function is symmetrical about the x = 1/2 vertical line

Algebra  christina, Tuesday, May 5, 2009 at 7:43pm
ok it says 1x=y and then a graph its equations
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