Posted by sh on Tuesday, May 5, 2009 at 3:27am.
Two cards are drawn without relplacement from a shuffled deck of 52 cards. Determine the probability of each event.
a)The first card is a heart and the second card is Q of hearts.
P(BlA)=P(A&B)/P(A)
(13/52)(1/51)/(1/4) = 1/51
How is this method incorrect?

math  Reiny, Tuesday, May 5, 2009 at 7:36am
I don't see why you are using the Conditional probability formula on this one.
you want the event to happen in a specific order, namely
one of the nonqueen hearts, and then the queen of hearts.
so
prob = 12/52 * 1/51 = 1/121

math  drwls, Tuesday, May 5, 2009 at 7:47am
In order for the second card to be the queen of hearts, the first card must be some other heart, and that has a probability of 12/52 = 3/13. Multiply that by the prob. of getting QH on the next draw, which is 1/51, and you get
3/663 = 1/221
Whatever you are doing with Bayesian probabilities P(BA), etc., is wrong.
1/51 is the probability of getting QH on the second draw, after getting ANYTHING ELSE on the first draw.

math  sh, Tuesday, May 5, 2009 at 10:48am
I was just taught this formula so I thought I'd use it, since one event comes after another.
Thank you.
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