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March 6, 2015

March 6, 2015

Posted by **sh** on Tuesday, May 5, 2009 at 3:27am.

a)The first card is a heart and the second card is Q of hearts.

P(BlA)=P(A&B)/P(A)

(13/52)(1/51)/(1/4) = 1/51

How is this method incorrect?

- math -
**Reiny**, Tuesday, May 5, 2009 at 7:36amI don't see why you are using the Conditional probability formula on this one.

you want the event to happen in a specific order, namely

one of the non-queen hearts, and then the queen of hearts.

so

prob = 12/52 * 1/51 = 1/121

- math -
**drwls**, Tuesday, May 5, 2009 at 7:47amIn order for the second card to be the queen of hearts, the first card must be some other heart, and that has a probability of 12/52 = 3/13. Multiply that by the prob. of getting QH on the next draw, which is 1/51, and you get

3/663 = 1/221

Whatever you are doing with Bayesian probabilities P(B|A), etc., is wrong.

1/51 is the probability of getting QH on the second draw, after getting ANYTHING ELSE on the first draw.

- math -
**sh**, Tuesday, May 5, 2009 at 10:48amI was just taught this formula so I thought I'd use it, since one event comes after another.

Thank you.

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