Question

You draw three tickets at random with replacement from the box. What is the chance that you draw at least one odd number? [Hint: A direct calculation of the chance might be hard, so Pascal and Fermat would subtract the chance of its opposite from 100%.]

You draw three tickets at random without replacement. What is the chance that you draw at least one odd number?

Please help!

Answer 1

Ooops sorry! I forgot to mention the box has 4 tickets {1,2,3,4} and whenever you pick a ticket out of the box, you replace it so that the first draw has no change on the chance of getting any ticket in the second draw.