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algebra

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Jack usually mows his lawn in 6 hours. Marilyn can mow the same lawn in 5 hours How much time would it take them to mow the lawn together?

  • algebra - ,

    In 30 hours, Jack mows 5 lawns, and Marilyn can mow 6 lawns.

    That is 11 lawns in 30 hours.

    rate=11/30 lawns/hr.

    so one lawn will take 30/11 hrs.

  • algebra - ,

    Jack's rate = job/6
    Marilyn's rate = job/5

    their combined rate = job/6 + job/5
    = 11job/30

    job = rate x time

    so time for combined effort = job/rate
    = job/(11job/30)
    = 30/11
    So it takes 30/11 hours
    = 2 8/11 hours

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