Posted by **anxious** on Monday, May 4, 2009 at 9:35pm.

Jack usually mows his lawn in 6 hours. Marilyn can mow the same lawn in 5 hours How much time would it take them to mow the lawn together?

- algebra -
**bobpursley**, Monday, May 4, 2009 at 9:51pm
In 30 hours, Jack mows 5 lawns, and Marilyn can mow 6 lawns.

That is 11 lawns in 30 hours.

rate=11/30 lawns/hr.

so one lawn will take 30/11 hrs.

- algebra -
**Reiny**, Monday, May 4, 2009 at 9:52pm
Jack's rate = job/6

Marilyn's rate = job/5

their combined rate = job/6 + job/5

= 11job/30

job = rate x time

so time for combined effort = job/rate

= job/(11job/30)

= 30/11

So it takes 30/11 hours

= 2 8/11 hours

## Answer this Question

## Related Questions

- Algebra - Jack usually mows his lawn in 4 hours. Marilyn can mow the same yard ...
- math - Jack usually mows his lawn in 4 hours. Marilyn can mow the same in 5 ...
- alegbra - Jack usually mows his lawn in 4 hours. Marilyn can mow the same yard ...
- Math - Jack usually mows his lawn in three hours. Marilyn can mow the same yard ...
- MATH - Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 5...
- algebra - jack usually mows his lawn in 4 hours mariltn can mow the same yard in...
- algebra - Jack usually mows his lawn in 4hrs Marilyn can mow the same yard in ...
- Algebra II - Jack usually mows his lawn in 6 hours. Marilyn can mow the same ...
- math/117 - Jack usually mowes his lawn in 7 hours. Marilyn can mow the same yard...
- algebra - Jack usually mows his law in 5 hours. Marilyn can mow the same law in ...