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July 24, 2014

July 24, 2014

Posted by **Kelslie** on Monday, May 4, 2009 at 8:28pm.

My work:

y=2cos((pi/6(x-d))+12

Ok how would I get the phase shift? Thanks in advance

- trig -
**Reiny**, Monday, May 4, 2009 at 10:13pmtreat one of the data values as input into your partial equation.

e.g. 14 hours in June --- y = 14, x = 5

14 = 2cos((pi/6(5-d))+12

2 = 2cos((pi/6(5-d))

1 = cos((pi/6(5-d))

so pi/6(5-d) = 2pi , because cos 2pi = 1

which solves for d = -7

your equation is

**y=2cos(pi/6)(x+7) + 12**

test it for one other given value.

e.g. Dec --> x = 11

y = 2cos(pi/6)18 + 12

= 2cos(3pi) + 12

= 2(-1) + 12

= 10 , as given

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