Monday

September 1, 2014

September 1, 2014

Posted by **gaberriel** on Monday, May 4, 2009 at 3:58pm.

- math -
**Reiny**, Monday, May 4, 2009 at 5:55pmlet the middle number be n

let the smallest be n-1

let the largerst be n+1

then

(n-1)+(n)+(n+1) = 417

3n = 417

n = 139

the numbers are 138, 139 and 140

or

let the smallest be x

the middle one be x+1

and the largest x+2

then x + x+1 + x+2 = 417

3x + 3 = 417

3x = 414

x = 138

notice now we found the first number, since we defined it that way, the other two are 139 and 140

Does the first method look easier?

- math -
**gaberriel**, Wednesday, May 6, 2009 at 2:43pmyes thankyou

**Related Questions**

math - i dont get this question consecutive integers are integers that differ by...

Math - The sum of three consecutive integers is 417. Let n be the first one. ...

math - i dont get this question consecutive integers are integers that differ ...

quad. eq. - find 3 consecutive integers such that the product of the second and ...

Math - When you solve questions like "The sum of 3 consecutive integers is 147. ...

math - A. Four times one odd integer is 14 less than three times the next even ...

math - 1. The largest of five consecutive integers is twice the smallest. Find ...

math - the sum of the reciprocals of three consecutive positive integers is ...

Algebra - There are three consecutive integers the square of the largest one ...

math plllls heelp - How many integers 1≤N≤1000 can be written both ...