Friday
May 22, 2015

Homework Help: chemistry

Posted by Brandon on Monday, May 4, 2009 at 10:59am.

What is the pH of the solution created by combining 2.40 mL of the 0.10 M NaOH(aq) with with 8.00 mL of the 0.10 M HC2H3O2(aq)?

So, here's my working so far:

.00024 mol NaOH
.0008 mol HC2H3O2
.0008 - .00024 = .00056 mol HC2H3O2

.00056mol / 0.0104L = .05385 M HC2H3O2

The Ka of acetic acid in water at 25C = 1.76 x 10^-5.

So I find [H+] = 9.73 x 10^-4

and pH = 3.01, but this is not the right answer. Can anyone explain where I went wrong?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Members