Friday

August 1, 2014

August 1, 2014

Posted by **xxx** on Sunday, May 3, 2009 at 3:09am.

2. What is the equation in slope-intercept form of the line described in Exercise 1?

can you please explain and answer it?? im having lots of trouble with this.

it's urgent... thanks a lot.. :)

- math -
**Reiny**, Sunday, May 3, 2009 at 8:33am1.

remember, an x-intercept of -3 is really the point (-3,0)

and a y-intercept of 6 is the point (0,6)

so slope of line = (6-0)/(0-(-3)) = 2

2.

so in y = mx + b, m is the slope and b is the y-intercept, so just put the stuff in there

y = 2x + 6

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