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Pre Cal

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Been trying to solve this equation and I keep getting 3...any advice would be appreciated

log2 (x+5)=4+log2 (x-1)

  • Pre Cal - ,

    log2[(x+5)/(x-1)] = 4
    2^4 = 16 = (x+5)/(x-1)
    16x - 16 = x + 5
    15x = 21
    x = 7/5

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