Posted by Isaac on Friday, May 1, 2009 at 9:03pm.
No, because if A is in W, then
B = lambda A
is not in W if lambda is not equal to 1:
A^x = A --->
B^x = lambda^x A^x = lambda^x A =
labda^(x-1) B
which is not equal to B for general lambda.
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