Posted by **Kelly** on Thursday, April 30, 2009 at 5:27pm.

Don't understand quadratic word problems at all. Please help, with steps.

One number is 8 more than another number. Their product is 273. find the numbers.

The differance between a number and twice it's reciprocal is 17/10. What is the number?

Thanks,

Kelly

- Algebra -
**Clark**, Thursday, April 30, 2009 at 6:35pm
y = x + 8

x*y = 273

x*(x+8) = 273

x^2 + 8x - 273 = 0

(x-13)(x+21) = 0

One of those factors must evaluate to 0 for the answer to be 0. Therefore, x must equal either 13 or -21.

y must equal either 21 or -13.

So: x=13 and y=21

or x=-21 and y=-13

I'm sure you can figure out the second one.

- Algebra -
**Quidditch**, Thursday, April 30, 2009 at 6:37pm
For the first problem:

Let x = lesser number

let y = greater number

(x) (y) = 273

The problem states that y = x + 8.

substituting for y:

(x) (x+8)=273

x^2 + 8x=273

so

x^2 + 8x - 273 = 0

Solve for x.

Then, y = x + 8

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