Posted by Anonymous on Monday, April 27, 2009 at 6:19pm.
tanx(cos^2 x - 1) = 0
tanx = 0 or cosx = ± 1
looking at tangents curves from -2pi to +2pi
x = -2pi , -pi, 0, pi, 2pi
looking at a cos curve where it is ±1
is -2pi, -pi 0, pi, and 2pi
so both parts had the same solutions,
x = 0, ±pi, ±2pi
Related Questions
math - Determine solutions for: tanxcos^2x - tanx = 0 in the interval[-2pi, 2pi]
Math-trigonometry - Several questions from my homework, any are appreciated. ...
More trig - Use the Quadratic Formula to solve the equation in the interval [0,...
trig - Solve cos x-1 = sin^2 x Find all solutions on the interval [0,2pi) a. x=...
Trig - Find all solutions of the equation on the interval [0,2pi): Tan^2x=1-secx
Trig - Find all solutions of equation on interval [0,2pi] 1=cot^2x + cscx
trig - Solve the equation for exact solutions over the interval [0, 2pi]. 4 cotx...
trig - 3tan(3x) = sqrt(3) Solve the equation for exact solutions of the interval...
trig - Find all solutions of the equation 2sin^2x-cosx=1 in the interval [0,2pi...
Trig - Solve for x in the interval [0,2pi) sin^2x+2cosx=2
For Further Reading
