Posted by Anonymous on Monday, April 27, 2009 at 6:19pm.
tanx(cos^2 x - 1) = 0
tanx = 0 or cosx = ± 1
looking at tangents curves from -2pi to +2pi
x = -2pi , -pi, 0, pi, 2pi
looking at a cos curve where it is ±1
is -2pi, -pi 0, pi, and 2pi
so both parts had the same solutions,
x = 0, ±pi, ±2pi
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