posted by Anonymous .
determine the exact value for sin[cos^-1(4/5)] if XE [0,2pi]
tells me the angle is in either I or IV, since the cosine is positive in the first and fourth quadrants.
make a sketch in the first quadrant, right-angled triangle with hypotenuse 5 and base of 4 (r=5, x=4)
by Pythagoras the other side is 3, or y=3
so in the first quadrant sin[cos^-1(4/5)] = 3/5
and in the fourth quadrant sin[cos^-1(4/5)] = -3/5
OK great! thank you so much