What do i do when order matters!!?!?

The Sad State Lottery requires you to select a sequence of three different numbers from zero through 64. (Order is important.) You are a winner if your sequence agrees with that in the drawing, and you are a y prize winner if your selection of numbers is correct, but in the wrong order. (Round all answers to three significant figures. Enter the answers in scientific notation.)

What is the probability of being a winner?

What is the probability of being a y prize winner?

What is the probability that you are either a winner or a y prize winner?

you need to find the permutation when order matters. look up the formula if you don't know it off hand. this should help you start...

Have no idea sorry buddy

To find the probabilities in this scenario, we need to consider the total number of possible outcomes and the number of favorable outcomes.

First, let's determine the total number of possible outcomes. Since we are selecting three different numbers from zero through 64, there are 65 choices for the first number, 64 choices for the second number (since it cannot be the same as the first), and 63 choices for the third number (since it cannot be the same as the first two). Therefore, the total number of possible outcomes is 65 * 64 * 63 = 261,360.

Now let's calculate the probability of being a winner. For the numbers to be in the correct order, there is only one favorable outcome. Therefore, the probability of being a winner is 1/261,360, which is approximately 3.82 x 10^(-6) in scientific notation.

Next, let's calculate the probability of being a y prize winner. In this case, the numbers must be correct, but in the wrong order. There are three ways to arrange the three numbers, so there are three favorable outcomes. Therefore, the probability of being a y prize winner is 3/261,360, which is approximately 1.15 x 10^(-5) in scientific notation.

Finally, let's calculate the probability of being either a winner or a y prize winner. Since these two outcomes are mutually exclusive (you cannot be both a winner and a y prize winner), we can simply add the probabilities of being each. Therefore, the probability of being either a winner or a y prize winner is (1/261,360) + (3/261,360), which simplifies to 4/261,360 or approximately 1.53 x 10^(-5) in scientific notation.