Posted by **Kim** on Friday, April 24, 2009 at 1:36am.

A painter needs to cover a triangular region 62 meters by 68 meters by 70 meters. A can of paint covers 70 square meters. How many cans will be needed?

- Trigonometry -
**drwls**, Friday, April 24, 2009 at 6:56am
Let s be half the sum of the three sides (100 m, in this case). If a, b and c are the side lengths of the triangle, the area is

sqrt[s(s-a)(s-b)(s-c)]

= sqrt[100*38*32*30] = 1910 m^2

1910/70 = 27.3 cans are needed

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