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Posted by on Friday, April 24, 2009 at 1:36am.

A painter needs to cover a triangular region 62 meters by 68 meters by 70 meters. A can of paint covers 70 square meters. How many cans will be needed?

  • Trigonometry - , Friday, April 24, 2009 at 6:56am

    Let s be half the sum of the three sides (100 m, in this case). If a, b and c are the side lengths of the triangle, the area is
    sqrt[s(s-a)(s-b)(s-c)]
    = sqrt[100*38*32*30] = 1910 m^2
    1910/70 = 27.3 cans are needed

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