Posted by **Laura** on Thursday, April 23, 2009 at 9:56pm.

how do you take a limit of [ln(1+e^n)]/2n as n goes to infinity?

- calculus -
**drwls**, Friday, April 24, 2009 at 12:29am
Take the limit of the ratio of the derivatives of numerator and denominator, with respect to n.

That ratio is the limit of

e^n/[2(1 + e^n)]

which approaches 1/2 since 1 becomes negligible compared to e^n, as n goes to infinity.

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