# Math, Pre-Calc

posted by
**Katie**
.

the original problem was:

Solve: sin(3x)-sin(x)=cos(2x)

so far i've gooten to:

sin(x)(2sin(x)cos(x)-1)=cos^2(x)-sin^2(x)

Where would I go from here?

posted by
**Katie**
.

the original problem was:

Solve: sin(3x)-sin(x)=cos(2x)

so far i've gooten to:

sin(x)(2sin(x)cos(x)-1)=cos^2(x)-sin^2(x)

Where would I go from here?