Posted by **Jon** on Thursday, April 23, 2009 at 1:52pm.

Identify the graph of the equation 4x^2-25y^2=100. Then write the equation of the translated graph for T(5,-2) in general form.

Might be another case of half right=all wrong.

I left off that it's a hyperbola

(x-h)^2/a^2 - (y-k)^2/b^2 = 1

x^2/25 - y^2/4 = 1

- Math -
**Reiny**, Thursday, April 23, 2009 at 3:34pm
x^2/25 - y^2/4 = 1 is the correct simplification of the original hyperbola

now according to your transformation

T(5,-2) I will asssume that you mean that

(x,y) ----> (x+5,y-2)

so the original centre of (0,0) would move to (5,-2) and your new equation is

[(x-5)^2]/25 - [(y+2)^2]/4 = 1

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