If P(a)=1/5, P(A and B)= 1/8, what is P(b/a)
i don't get it is it the same way as finding p or b or is it something entirely different and how do you find it
I think you are dealing with "conditional probability"
usually written as P(B│A) and read as
"the probability of B given A"
P(B│A) = P(A and B)/P(A)
= (1/8) / (1/5)
= 5/8
so it would be division then i would have to cross multiply right??? by the way thank you...Alot!
You are dividing 2 fractions at the end
(1/8) / (1/5)
= (1/8) ÷ (1/5)
= (1/8)x(5/1)
= 5/8
To find P(B|A), which represents the probability of event B occurring given that event A has already occurred, you can use the formula:
P(B|A) = P(A and B) / P(A)
Given that P(A) = 1/5 and P(A and B) = 1/8, you can substitute these values into the formula to calculate P(B|A).
P(B|A) = (1/8) / (1/5)
To simplify this expression, divide 1/8 by 1/5. Invert the divisor and multiply the fractions:
P(B|A) = (1/8) * (5/1) = 5/8
Therefore, P(B|A) is equal to 5/8.