Posted by **Jon** on Wednesday, April 22, 2009 at 3:22pm.

Write the standard form of the equation of the circle that passes through (0,4) and has its center at (-3,-1).

(x-h)^2 + (y-k)^2 = r^2

(x+3)^2 + (y+1)^2 = r^2

r^2 = d

d = sqrt(x2-x1)^2 +(y2-y1)^2

d = sqrt(-3-0)^2 + (-1-4)^2

d = 3^2 + -5^2

d = sqrt34

(x+3)^2 + (y+1)^2 = r^2

(x+3)^2 + (y+1)^2 = sqrt34 <--(answer)

I got half off, she just circled the sqrt34 part

- Math -
**Reiny**, Wednesday, April 22, 2009 at 3:32pm
for a circle with centre (h,k) and radius r

the standard form is

(x-h)^2 + (y-k)^2 = r^2

your right side should have been 34 not √34

BTW, an easier and quicker way would be to start with

(x+3)^2 + (y+1)^2 = r^2 , now sub in (0,4)

9 + 25 = d^2 = 34

put that back in, done!

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