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Write the standard form of the equation of the circle that passes through (0,4) and has its center at (-3,-1).

(x-h)^2 + (y-k)^2 = r^2
(x+3)^2 + (y+1)^2 = r^2
r^2 = d
d = sqrt(x2-x1)^2 +(y2-y1)^2
d = sqrt(-3-0)^2 + (-1-4)^2
d = 3^2 + -5^2
d = sqrt34

(x+3)^2 + (y+1)^2 = r^2
(x+3)^2 + (y+1)^2 = sqrt34 <--(answer)

I got half off, she just circled the sqrt34 part

  • Math -

    for a circle with centre (h,k) and radius r
    the standard form is
    (x-h)^2 + (y-k)^2 = r^2

    your right side should have been 34 not √34

    BTW, an easier and quicker way would be to start with
    (x+3)^2 + (y+1)^2 = r^2 , now sub in (0,4)
    9 + 25 = d^2 = 34
    put that back in, done!

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