A current-carrying wire is oriented at right angles to a uniform magnetic field. If the length of the wire is

0.50 m and it experiences a force of 0.90 N while carrying a current of 4.0 A, what is the strength of the magnetic field?

I did the work and got:
0.45 ...???

In this situation,

F = B I L

where L is the length of the wire.

Therefore,

B = F/(IL)

You got the correct number. The units are Teslas (T)

yes, 0.45 T thanks for checking!

To find the strength of the magnetic field, we can use the formula for the force on a current-carrying wire in a magnetic field:

F = BIL

Where:
F is the force on the wire,
B is the magnetic field strength,
I is the current flowing through the wire, and
L is the length of the wire.

In this case, we are given:
F = 0.90 N (force on the wire),
I = 4.0 A (current flowing through the wire), and
L = 0.50 m (length of the wire).

Plugging these values into the formula, we can solve for the magnetic field strength (B):

B = F / (IL)

B = 0.90 N / (4.0 A * 0.50 m)

B = 0.90 N / 2.0 A*m

B = 0.45 T (tesla)

So, the strength of the magnetic field is 0.45 T.

To find the strength of the magnetic field, we can use the formula for the magnetic force on a current-carrying wire in a uniform magnetic field, which is given by the equation:

F = BILsinθ

Where:
F = magnetic force on the wire
B = strength of the magnetic field
I = current flowing through the wire
L = length of the wire
θ = angle between the wire and the magnetic field

In this case, the wire is oriented at right angles to the magnetic field, so the angle θ is 90 degrees.

Given:
F = 0.90 N
I = 4.0 A
L = 0.50 m
θ = 90 degrees

Plugging in the values into the formula:

0.90 N = B * 4.0 A * 0.50 m * sin(90 degrees)

Since sin(90 degrees) = 1, we can simplify the equation to:

0.90 N = B * 4.0 A * 0.50 m

Now, solve for B:

B = 0.90 N / (4.0 A * 0.50 m)

B = 0.90 N / 2.0 A*m

B = 0.45 Tesla

So, the strength of the magnetic field is 0.45 Tesla.