PHYSICS
posted by Sandy on .
A hollow tube (I = MR2) rolls without slipping along the surface. The ratio of its translational kinetic energy to its rotational kinetic energy is
a. 1
b. 2
c. 3
d. 1/2
e. 1/3
I say A becasue both add up to get the total kinetic energy.

Translational KE is (1/2) M V^2
Rotational KE is (1/2)I w^2
= (1/2) M R^2*(V/R)^2 = (1/2) M V^2
Your answer is correct but your reasoning is faulty. The ratio could be anything and they would still add up to give total KE 
The Answer is "I don't know. Ask I".