Posted by **Sandy** on Wednesday, April 22, 2009 at 1:15pm.

A hollow tube (I = MR2) rolls without slipping along the surface. The ratio of its translational kinetic energy to its rotational kinetic energy is

a. 1

b. 2

c. 3

d. 1/2

e. 1/3

I say A becasue both add up to get the total kinetic energy.

- PHYSICS -
**drwls**, Wednesday, April 22, 2009 at 3:53pm
Translational KE is (1/2) M V^2

Rotational KE is (1/2)I w^2

= (1/2) M R^2*(V/R)^2 = (1/2) M V^2

Your answer is correct but your reasoning is faulty. The ratio could be anything and they would still add up to give total KE

- PHYSICS -
**First Name**, Monday, April 1, 2013 at 7:03am
The Answer is "I don't know. Ask I".

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