Posted by **Riley** on Wednesday, April 22, 2009 at 10:28am.

V(h) = pie/3(R^2h-h^3)

take the derivative with respect to h.

using the chain rule I got:

V'(h) = pie/3(2Rh+R^2-3h^2)

but this is not the correct answer. what did I do wrong?

- calculus -
**drwls**, Wednesday, April 22, 2009 at 10:37am
I would prefer to write the V equation as

V(h) = (pi/3)(R^2*h-h^3)

to emphasize that the (R^2h-h^3)

term is not in the denominator.

Unless R is a function of h, you do not have to use the chain rule. You have said nothing that implies that R is a function of h. R and h are independent variables. ÝV/Ýh is really a partial derivative.

Consider R as a constant when differentiating with respect to h.

V'(h) = (pi/3)R^2 - pi*h^2

- calculus -
**drwls**, Wednesday, April 22, 2009 at 10:39am
Ignore ÝV/Ýh

Jiskha would not allow me to type the rounded-d symbol for d in the partial derivative.

- calculus -
**Riley**, Wednesday, April 22, 2009 at 10:44am
thanks!

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