Posted by **Henri** on Wednesday, April 22, 2009 at 9:01am.

Lubricating oil, with a relative density of 0.79, flows around a 90¨¬ bend. The pipe diameter is 0.45m, and the oil has a pressure head of 7m and the flow is 1.7m3/s. Find the force exerted by the oil on the bend.

Oil density = 0.79 X 103

Volumetric mass flow rate = 1.7 m3/s

Pipe diameter = 0.45 m

Pressure head (¥÷) = 7m

Oil mass flow=density*Vol/sec

Mass flow=0.79X10^3*1.7

Mass flow=1343kg/sec

Oil velocity in the pipe:

Vel.*pir^2=1.7m^3/sec

vel.=1.7/pi*(0.45/2)^2

vel of oil=10.69m/s

Force(F1) on the bend due to oil flow:

F1=Oil mass flow*Oil velocity

F1=1343*10.69

F1=14356kgm/s^2 or 14.356kN

Force(F2) due to oil pressure:

Pressure=press. head*(density*gravity)

p=7m*0.79X10^3kg/m^3*9.81m/s^2

p=54249kg/ms^2

F2=pA

F2=54249kg/ms^2*(0.7854X0.45^2)

F2=8627kgm/s^2 or 8.627kN

Total Force(Ft) acting on elbow:

Ft=F1+F2

Ft=14.3456kN+8.627kN

Ft=22.983kN (ans.)

Thanks for taking a look.

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