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December 21, 2014

December 21, 2014

Posted by **strate a stoodent** on Tuesday, April 21, 2009 at 9:51pm.

(1) 9x^2 + 9y^2 + 18x - 18y = 0

(2) 16x^2 + 16y^2 - 64x + 32y + 55 = 0

(3) 6x^2 + 2y^2 + 18x - 10y + 2 = 0

- Pre-Cal -
**Reiny**, Tuesday, April 21, 2009 at 9:57pmthe first two are circles, the last one is an ellipse

I will do the second one by

completing the square,

16x^2 + 16y^2 - 64x + 32y + 55 = 0

16(x^2 - 4x+ ___) + 16(y^2 + 2y + ___) = -55

16(x^2 - 4x+ 4) + 16(y^2 + 2y + 1) = -55+64+16

16(x^2 - 4x+ 4) + 16(y^2 + 2y + 1) = 25

(x-2)^2 + (y+1)^2 = 25/16

- Pre-Cal -
**Straight-A Student**, Tuesday, April 21, 2009 at 10:02pmOh, I see what I was doing wrong. I thought you had to SUBTRACT the numbers from the other side when you complete the square, but you have to ADD them. I get it now. Thanks!

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