Posted by strate a stoodent on Tuesday, April 21, 2009 at 9:51pm.
the first two are circles, the last one is an ellipse
I will do the second one by
completing the square,
16x^2 + 16y^2 - 64x + 32y + 55 = 0
16(x^2 - 4x+ ___) + 16(y^2 + 2y + ___) = -55
16(x^2 - 4x+ 4) + 16(y^2 + 2y + 1) = -55+64+16
16(x^2 - 4x+ 4) + 16(y^2 + 2y + 1) = 25
(x-2)^2 + (y+1)^2 = 25/16
Oh, I see what I was doing wrong. I thought you had to SUBTRACT the numbers from the other side when you complete the square, but you have to ADD them. I get it now. Thanks!
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