How many grams of NaCL are required to make 250ml of a 0.4M solution?
M = mols/liter of solution.
#moles = grams/molar mass.
Molar mass for Nacl= 58.44g/mol Volume=250ml or 0.250Litre molarity=0.4M °grams of NaCl required=Molarity × Volume in litre × Molar mass of NaCl=0.4M×0.250L×58.44g/mol=5.844g. There for 5.844g of NaCl is required to prepare 500ml of 0.4M solution NaCl. Weigh 5.844g of NaCl powder and dissolve in 500ml of Distilled water. BY BELLO LAWAL DANCHADI (STUDY HARD) FROM UDUSOK.
To calculate the grams of NaCl required to make a 0.4M solution in 250ml, we need to use the formula:
moles of solute = molarity × volume (in liters)
First, let's convert the volume to liters:
250ml = 250ml × 1L/1000ml = 0.25L
Next, substitute the values into the formula:
moles of solute = 0.4M × 0.25L = 0.1 moles
Finally, we need to convert moles to grams by using the molar mass of NaCl. The molar mass of NaCl is approximately 58.44 grams/mole.
grams of NaCl = moles of solute × molar mass
grams of NaCl = 0.1 moles × 58.44 grams/mole
grams of NaCl = 5.844 grams
Therefore, you would require approximately 5.844 grams of NaCl to make a 250ml 0.4M solution.
To calculate the number of grams of NaCl required to make a 0.4M solution, you need to know the molar mass of NaCl and the volume of the solution.
The molar mass of NaCl is 58.44 g/mol, which means that one mole of NaCl weighs 58.44 grams.
First, you need to find the number of moles of NaCl required to make a 0.4M solution. The Molarity (M) is defined as the number of moles of solute (NaCl) per liter of solution.
Molarity (M) = Moles of solute / Volume of solution (in liters)
Rearranging the equation, we get:
Moles of solute = Molarity (M) x Volume of solution (in liters)
Since the volume given in the question is in milliliters, we need to convert it to liters by dividing it by 1000:
Volume of solution (in liters) = 250 ml / 1000 = 0.25 liters
Now, substitute the values into the equation:
Moles of solute = 0.4 M x 0.25 L = 0.10 moles
Finally, to get the number of grams of NaCl, multiply the number of moles by the molar mass:
Grams of NaCl = Moles of solute x Molar mass
= 0.10 moles x 58.44 g/mol
= 5.844 grams
Therefore, you would need approximately 5.844 grams of NaCl to make 250 ml of a 0.4M solution.