I know the answer to this question, but I want to find a simpler way of doing it...
---Find the sum of the counting numbers from 1 to 25 inclusive. In other words, if S= 1+2+3+...+24+25, find the value of S.
Thanks!!!!!
It can also be designated as "S!", which is said as "S factorial." It means
S + (S-1) + (S-2)...3 + 2 + 1
Does that help? Thanks for asking.
S=325
Sorry, super late. You most likely wouldn’t see this, but whoever does, here is a shortcut.
n*(n + 1) n*a
———— = —— = n*b = x n + 1 = a
2 2 a/2 or 1/2*a = b
25*(25 + 1) 25*26 n*b = x
————— = ———— = 25*13 = 325
2 2
There is also a “rainbow” method.
Example: Find the sum of the counting numbers from 1 to 10 inclusive.
1 + 10 = 11
2 + 9 = 11
3 + 8 = 11
4 + 7 = 11
5 + 6 = 11
The method I put above the rainbow method is basically a more efficient version of the rainbow version. I hope this didn’t confuse you, and also hope this was helpful!
Best regards,
A young elementary schooler.
To find the sum of the counting numbers from 1 to 25 inclusive, there is a simple mathematical formula you can use. The sum of an arithmetic series can be calculated using the formula: S = (n/2)(a + l), where S is the sum, n is the number of terms, a is the first term, and l is the last term.
In this case, the first term is 1 and the last term is 25, so we can substitute those values into the formula. The number of terms, n, can be found by subtracting the first term from the last term and adding 1. So, n = 25 - 1 + 1 = 25.
Using the formula, S = (25/2)(1+25) = (25/2)(26) = 325.
Therefore, the sum of the counting numbers from 1 to 25 inclusive is 325.