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September 17, 2014

September 17, 2014

Posted by **jason** on Monday, April 20, 2009 at 7:52pm.

- algebra -
**Damon**, Monday, April 20, 2009 at 8:02pmDo the (3x+5)(10x+2) first and multiply by 3x later.

Do you know FOIL (first, outer, inner, last) ?

If so use it:

3x [ 3x*10x + 3x*2 + 5*10x + 5*2]

= 3x [ 30 x^2 + 56 x + 10 ]

If you do not know FOIL, use distributive property directly:

= 3x [ 3x(10x+2) + 5(10x+2) ]

= 3x [ 30 x^2 + 6x + 50x + 10 ]

= 3x [ 30 x^2 + 56 x + 10 ] which we already knew from FOIL

now do the 3x times

= 90 x^3 + 168 x^2 + 30 x

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