How many Coulombs of charge pass through a 95W amplifier plugged into 110V wall socked over the course of a 2 hour concert?
75240000 Coulombs
I also need help with a similar question:
What is the charge that passes through a 95 W amplifier plugged into a 110 V wall outlet over the course of a 60 minute concert?
To determine the number of Coulombs of charge that pass through the amplifier, we can use the formula:
Charge (Q) = Power (P) × Time (t) / Voltage (V)
Given:
Power (P) = 95W
Time (t) = 2 hours = 2 × 60 minutes = 120 minutes
Voltage (V) = 110V
First, let's convert the time to seconds to ensure consistency in units:
Time (t) = 120 minutes × 60 seconds/minute = 7200 seconds
Now we can substitute the given values into the formula:
Q = 95W × 7200s / 110V
Next, we can calculate the value of Q:
Q = (95W × 7200s) / 110V
Q ≈ 6218.18 Coulombs
Therefore, approximately 6218.18 Coulombs of charge pass through the 95W amplifier over the duration of the 2-hour concert.
Multiply the current in Amps (Power/Voltage) by the number of seconds (7200).
Actually the same charge will go back and forth, since it is certainly an AC circuit.