Posted by kim on Sunday, April 19, 2009 at 6:52pm.
cot 2x = 1/tan 2x
= 1/[2tanx/(1-tan^2(x))]
= (1-tan^2(x))/2tanx
= [1 - 1/cot^2(x))/(2/cotx)
= [(cot^2(x) - 1)/cot^2(x)]/[2/cotx]
= (cot^2(x) - 1)/(2cotx)
I don't know if that is the simplest way, I just sort of followed by nose.
you can try sec 2x by noting
sec 2x = 1/cos 2c
then using cos2x = 2cos^2(x) - 1
follow the above procedure.
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