Yes to the ICE table (at least a modified one) and no, there is no limiting reagent.
First you want to determine the moles HCl and moles H3PO4 mixed. M x L = moles.
All of that is added to a 1 L volumetric flask, diluted to the mark. So what is the concn of HCl and H3PO4. Obviously, its just moles HCl/1000 and moles H3PO4/1000. Now you take 50 mL of that, so M x L again gives you moles of the titrated amount in the 50 mL portion. That's the hard part. The easy part is next.
Remember H3PO4 is a weak acid with three H ions to titrate but HCl is a strong acid. So the HCl will be titrated first, then the first H of the H3PO4, then an equal amount for the second H of the H3PO4. Add amount HCl + H #1 H3PO4 + H #2 for H3PO4 and that is the total volume for th HCl plus two hydrogens from the H3PO4. Technically, the third H from H3PO4 can't be titrated; however, it can be if one adds Ca^+2 [to ppt all of the phosphate ion as Ca3(PO4)2]
Check my thinking. Post your work if you get stuck.
So far i got .118 mol of HCl than divided by 1000 which got me 1.18e-4 than i times that by .050 L =5.59E-6 moles. i than did the same thing for the H3PO4 and got for the final answer 1.82E-5. I'm confused on your meaning for than getting the concentration of the two. Right now they are both in moles i need to get them into molarity and than plug into ice table right. i than need the ka value right? or is this not a correct way to do it?
We're not on the same page.
If you have 0.118 moles HCl in 1 L, then the molarity is #mols/L so it must be 0.118 M. (After re-reading my first response, I probably mis-led you. I was calculating mols/mL and when multiplied by the 50 mL aliquot you would have the moes in the final mixture). The concn H3PO4 is # moles/L = 0.03370 x 10.80 M = 0.3640 moles/L = 0.3640 M.
If we take 50 mL of that 1 L solution, we now have M x L = 0.118 M x 0.050 L = ?? moles HCl and we have 0.3640 M x 0.050 L = ?? moles H3PO4.
Now you titrate that mixture with 0.2200 M NaOH. Neutralize the HCl first, then the first H on the H3PO4, then the second H on the H3PO4 and add the 3 volumes together.