Posted by **jeff** on Sunday, April 19, 2009 at 12:31am.

You are in a hot-air balloon that ascends at a constant velocity of 2.00 m/s. When the ballon is 1000 meters in the air you jump out of it what speed will you hit the ground with? neglect air resistance.

I know we use the conservation of mechanical energy to solve this my question is will my initial velocity be 2.00 m/s or will it be zero because iam at rest in the ballon.

- physics -
**TchrWill**, Sunday, April 19, 2009 at 10:23am
Technically, when you detach yourself from the balloon, you have an initial upward velocity of 2m/s which, after 0.20sec, you will rise .204m.

Ignoring this, the time to reach the ground derives from h = Vot + gt^2/2 or 1000 = o(t) + 9.8t^2/2 yielding a falling time of 14.28 sec.

The velocity with which you hit the ground derives from Vf = Vo + 9.8t = 0 + 9.8(14.28) = 140m/s.

The "exact" answer combines the two results.

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