Posted by Joanne on Saturday, April 18, 2009 at 2:18am.
The concn of what in the diluted solution? the original sample or the ASA in the original sample? And what kind of units for the concn?
The original sample is
(0.400 g/250 mL) x (3 mL/100 mL) = ?? g/mL
If you want the concn ASA, you start with 0.4 x 0.682 = ?? and use that number in place of the 0.400 g.
If you want molarity, change the first solution to molarity.
0.400 x 0.682 x (1 mol/180.16 g) x 1000 mL/250 mL then the dilution is x (3 mL/100 mL) = ?? M.
Check my work.
Your work is correct, DrBob222. Thanks for the help
so whats the actual answer for the concentration? i keep trying and im getting the wrong answer.
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