Posted by **Lena** on Friday, April 17, 2009 at 12:39am.

You are driving 2500 Kg car at a constant speed of 14 m/s along an icy, but stright and lvel road. While approaching a traffic light, it turns red. You slam on the brakes. You wheels lock, the tires begin skidding and the car slides to a halt in a distance of 25 m. What is the coefficient of sliding friction between the tires and the icy road?

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Calculations:

m = 2500 Kg

Vi = 14 m/s

Vf = 0 m/s

deltaD = 25 m

a = (vf^2 - vi^2)/(2 x deltaD)

= -14 m/s / 50

= 2.8 m/s^2

W = (2500) (9.81)

= 24525 N

Fnet = (2500)(-0.28)

= -700 N

I`m not sure what to do after this.

- Physics -
**drwls**, Friday, April 17, 2009 at 1:53am
(friction force) x (distance of skid) = Kinetic energy loss

Use that equation to get the friction force, f.

The coefficient of kinetic friction, Uk, can be obtained from

Uk = f/(M*g)

- Physics -
**Lena**, Friday, April 17, 2009 at 2:03am
oh ok thanks :)

- Physics -
**aadi**, Monday, December 13, 2010 at 2:14am
dont forget its 14^2/50 - -3.92m/s^2

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