Saturday

August 30, 2014

August 30, 2014

Posted by **Lena** on Friday, April 17, 2009 at 12:39am.

-------------------------------------

Calculations:

m = 2500 Kg

Vi = 14 m/s

Vf = 0 m/s

deltaD = 25 m

a = (vf^2 - vi^2)/(2 x deltaD)

= -14 m/s / 50

= 2.8 m/s^2

W = (2500) (9.81)

= 24525 N

Fnet = (2500)(-0.28)

= -700 N

I`m not sure what to do after this.

- Physics -
**drwls**, Friday, April 17, 2009 at 1:53am(friction force) x (distance of skid) = Kinetic energy loss

Use that equation to get the friction force, f.

The coefficient of kinetic friction, Uk, can be obtained from

Uk = f/(M*g)

- Physics -
**Lena**, Friday, April 17, 2009 at 2:03amoh ok thanks :)

- Physics -
**aadi**, Monday, December 13, 2010 at 2:14amdont forget its 14^2/50 - -3.92m/s^2

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