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January 31, 2015

January 31, 2015

Posted by **Joshua** on Thursday, April 16, 2009 at 10:47pm.

I let an = (1+sin(n))/(10^n) and bn = 1/10^n

lim as n approaches positive infinity = an/bn = ((1+sin(n))/(10^n))/(1/(10^n))= 1+sin(n)= positive infinity.

I don't know if it's right or not but if someone could look over it that would be great.

- Calculus -
**Reiny**, Friday, April 17, 2009 at 8:37amI ran this simple Quick-Basic program

FOR N = 1 TO 20

TERM = (1+ SIN(N))/(10^N)

SUM = SUM + TERM

PRINT TERM, SUM

NEXT N

the terms keep getting smaller by appr a factor of 10, (obviously the denominators become 1,10,100,1000, ...)

since the sin(N) can only be a number between -1 and 1, then (1+sin(n)) will range between 0 and 2

after about 7 terms, the sum had approached a value of 1.204407 and since each successive term would be smaller than 10^-7, it would converge to that sum.

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