Posted by **Anonymous** on Thursday, April 16, 2009 at 7:40pm.

Write the standard form of the equation of a circle that passes through the points at (0,8) (8,0) and (16,8). Then identify the center and radius of the circle.

(x-8)^2 + (y-8)^2 = 64

(x^2 / 64) + (y^2 / 64) = 64

center=(8,8)

radius=8

I got it wrong don't know how

- Advanced Math -
**Anonymous**, Thursday, April 16, 2009 at 7:49pm
(x-8)^2 + (y-8)^2 = 64

fine

(x^2 / 64) + (y^2 / 64) = 64

but where did you get this??????

center=(8,8)

fine

radius=8

fine

- Advanced Math -
**bobpursley**, Thursday, April 16, 2009 at 7:54pm
You will have to write the equation

(x-h)^2+(y-k)^2=r^2

for the three sets of points given. Then solve for h, k, r

It is ugly but solvable.

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