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Find the principle root (-64)1/6. Express the result in the form a+bi.

(2i)^6= -64 = (-64)1/6= 0+2i

I got it wrong, please help.

  • Advanced Math -

    you have 64@180 on the complex plane.

    the sixth root of that is ..
    2@30

    in rectangular coordinates...
    2cos30+2isin30

    Try that.

  • Advanced Math -

    Ok but are you sure it's ok for how they want me to express it?

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