Find the length and width of a rectangular lot with a perimeter of 70 meters if the length is 5 meters more than the width
l-5=w
2l+2w=70
2l+2(l-5)=70
solve for l first.
To find the length and width of a rectangular lot with a given perimeter, we can set up two equations based on the given information.
Let's assume the width of the lot is "w" meters. According to the problem, the length is 5 meters more than the width, so we can say the length is "w + 5" meters.
The perimeter of a rectangle is the sum of the lengths of all its sides. For a rectangle, the formula for perimeter is: P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.
In this case, the perimeter is given as 70 meters. So we can set up the equation:
70 = 2(w + w + 5)
Simplifying the equation:
70 = 2(2w + 5)
70 = 4w + 10
Subtracting 10 from both sides:
60 = 4w
Dividing both sides by 4:
w = 15
Now, we have found the width of the rectangular lot, which is 15 meters. To find the length, we can substitute this value back into the equation for the length:
l = w + 5
l = 15 + 5
l = 20
Therefore, the length of the rectangular lot is 20 meters and the width is 15 meters.