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Posted by on Wednesday, April 15, 2009 at 10:38pm.

Find an equation of the tangent line to the parabola at the given point, and find the x-intercept of the line.

17) x^2=2y , (-3,9/2)

18) y=-2x^2 , (-1,-2)

  • Pre-Cal - , Thursday, April 16, 2009 at 12:57am

    I'll do one of them. Use the same method for the other.

    17) y = x^2/2 and the slope of the parabola is dy/dx = x
    When x = -3, y = 9/2 and the slope is -3. A straight line going through (-3, 9/2) with slope -3 has the equation
    y - 9/2 = -3[x -(-3)]
    y = -3x + 9/2 -9 = -3x -9/2
    The x intercept (where y = 0) is
    x = -3/2

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