Posted by Sandy on Wednesday, April 15, 2009 at 9:55am.
a) h = 10(.75)^n
that is basically what you had
b) d = 10 + 10(.75)^1 + 10 (.75)^2 + 10(.75)^3 .... In other words I sort of agree with you
c) This is a geometric series like a
compound interest problem
in general
g + gr + gr^2 + .... gr^(n-1)
Sn = [ g (1-r^n ]/ (1-r)
here g = 10 and r = .75
so
Sn = [ 10 (1 - .75^n) /.25
I disagree with part b)
at the first bounce the ball has traveled 10 ft.
at the second bounce, it went up 7.5 and then down 7.5, so
distance after two bounces = 10 + 2(10)(.75)^1
after 3 bounces it went 10 + 2(10)(.75) + 2(10)(.75)^2
so after the first bounce, you have to double the distance, since it goes up and then the same distance down again.
so the series
= 10 + 2(10)(.75) + 2(10)(.75)^2 + 2(10)(.75)^3 + ....
so
Sn = 10 + 20(.75)[1 - .75^(n-1)]/(1 - .75)
so I see an infinite geometric series starting with the second term and that sum is
10 + (20)(.75)/(1 - .75)
= 10 + 15/.25
= 70 feet
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