The crystal structure of lithium sulfide (Li2S) is pictured here. The length of the unit cell is 5.88 x 10^2. For this structure, determine:
(I could not paste the actual picture from the assignment here, but if you go to Google Image and type in "crystal structure of lithium sulfide" the first picture represents the same one on my assignment). - This website would not let me post another internet address. This is why I had to do it this way)!
a)the coordination number of Li and S
b) the number of formula nunits in the unit cell
c) the density of Li2S
Thanks!
To determine the information requested for the crystal structure of lithium sulfide (Li2S), we need to use the given length of the unit cell, which is 5.88 x 10^2.
a) The coordination number refers to the number of nearest neighbors an atom has in a crystal lattice. To determine the coordination number of Li and S, we need to examine the crystal structure.
b) The number of formula units in the unit cell can be calculated using Avogadro's number and the molar mass of Li2S.
c) The density of Li2S can be found by using the formula: density = mass/volume. We can calculate the mass by multiplying the molar mass of Li2S by the number of formula units in the unit cell, and the volume can be found by using the formula: volume = (length of unit cell)^3.
To find the answers to these questions more accurately, it is recommended to refer to the provided picture of the crystal structure or consult a reliable source that shows the crystal structure of lithium sulfide.