Tuesday
September 2, 2014

Homework Help: Calc.

Posted by Joshua on Tuesday, April 14, 2009 at 8:52pm.

Let h(x)=16-4x-(x^3)
Find g(96).

My work:
96= 16-4x-(x^3)
(-x^3)-4x-80=0
Using the rational roots theorm, I found that x=-4
so h(-4)=96, therefore g(96)=-4.

Find g'(96).

My work:
g'(96)= 1/(dh/dx at x=-4)
1/((-3(-4)^2)-4)= -1/52

Does this look ok? Also, my math teacher wanted us to find two ways to do this problem and get the same answer. I found one way, but I can't think of another. Any suggestions?

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