Physics
posted by Malcom on .
A gun that is springloaded shoots an object horizontally. The initial height of the gun is h=5 cm and the object lands 20 cm away. What is the gun's muzzle velocity?
Do i use something like v=sqr(k)/m*x. I am getting something like 3.2, is this somewhat correct at all.

3.2 with what dimensions?
The muzzle velocity Vx is given by
Vx*T = 0.2 m
where T is the time it takes the bullet to fall 0.05 m.
0.05 m = (1/2) g T^2
T = sqrt (0.101 s)
Complete the solution for Vx = 0.2m/T, , the muzzle velocity 
I am getting .625m/s with your way, but the choices I have are
a. 2.0 m/s
b. 1.0 m/s
c. 3.2 m/s
d. 4.9 m/s
e. 3.9 m/s