Posted by Steve on Tuesday, April 14, 2009 at 5:28pm.
If the Ag^+ were at the standard state of 1.0 M, then Ecell would have been 0.700 v.
It isn't, so
Ehalf cell = Eo-(0.0592/n)log(red/ox)
Ehalf cell is 0.617, Eo = 0.700, n is 1 for the number of electrons, the reduced form is Ag so that is 1 in the standard state (solid), and the oxidized form is x. Solve for x.
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