math
posted by jake .
How do i write an equation in point slope form of a line that passes through (6,5) and has a x intercept of 3...also how do i make it into slope intercept form

the xintercept of 3 corresponds to the point (3,0)
so the slope is (50)/(6+3) = 5/9
then
y  5 = (5/9)(x6)
9y  45 = 5x  30
9y = 5x + 15
y = (5/9)x + 15/9
y = (5/9)x + 5/3