posted by Steve .
mol KHP = (0.7719g)(1 mol KHP/204.2g) = .0038mol
Where are the moles of NaOH?
I know that there are 0.02637 L of NaOH
and I know M = mol/l
I know there are 40g NaOH/mol NaOH
There is 1 mol of NaOH in the balanced equation
But I do not have grams of NaOH
If you know M = mol/L, doesn't it follow that mols = M x L? :-)
So mols NaOH = M(NaOH) x L(NaOH).
mols NaOH = mols KPH (from the titration)
L(NaOH) is given.
Solve for M(NaOH) which is what you want.
The whole concept of a titration is that you are adding moles of one reagent (from a buret, usually) to moles of another reagent (either in solid form or liquid form) and you have an indicator that tells you when to stop. [Technically, you are adding equivalents of one reagent to equivalents of another reagent]. But the NEW chemistry doesn't use equivalents. Pity.