posted by Steve on .
Potassium hydrogen phthalate (molar mass = 204.2g/mol) is used to standardize sodium hydroxide. If 26.37 mL of NaOH(aq) is required to titrate 0.7719g KHP to the equivalence point, what is the concentration of the NaOH(aq)
(26.37 mL NaOH)(x) = (1 mol KHP/.7719g KHP)(204.2g KHP/mol KHP)
I think it would be easier to do this in steps. I think you are confusing yourself in trying to do it all in one step.
mols KHP = 0.7719 g x (1 mol/204.2 g) = ?? (which is the inverse of what you have written. Look at the units for the right side of what you wrote. mols cancels with mols and g cancels with g so the right hand side of your equation, which should come out in moles, is unitless).
mols NaOH = same thing (that's when the indicator tells you that mols of one = moles of the other---to be more exact when the equivalents of one = equivalents of the other).
mols NaOH = M x L.
You know mols NaOH and L, calculate M.
I don't get anything close to 10 M.