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Posted by on Tuesday, April 14, 2009 at 7:50am.

Near Earth, the density of protons in the solar wind (a stream of particles from the Sun) is 12.4 cm-3, and their speed is 576 km/s. (a) Find the current density of these protons. (b) If Earth's magnetic field did not deflect the protons, what total current in amperes Earth receive?

  • electric physics - , Tuesday, April 14, 2009 at 9:33am

    change km/s to cm/s, then multiply density given times speed.

    Current = current density*area crosssection earth/charge per proton

  • electric physics - , Tuesday, April 14, 2009 at 9:45am

    For part (b), multiply the current density (from part a) by pi R^2, where R is the radius of the Earth.

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